Browns’ Denzel Ward becomes NFL’s highest-paid DB with two-year, $62.2 million extension, AP source says

Browns’ Denzel Ward becomes NFL’s highest-paid DB with two-year, $62.2 million extension, AP source says

CLEVELAND — Denzel Ward has agreed to a two-year extension with the Browns that will make him the highest-paid defensive back in the NFL, a person familiar with the deal told The Associated Press.

Read more Jordan intercepts Iranian missiles as US and Saudi Arabia launch strikes against militias in Iraq

The five-time Pro Brown cornerback will sign a two-year extension worth $62.2 million — including $52.3 million guaranteed, the person told the AP on condition of anonymity because the deal had not been publicly announced.

The $31.1 million average surpasses the $31 million average when Trent McDuffie signed a four-year, $124 million contract with the Rams after being traded by the Chiefs in March.

Related: Christian Gonzalez declines to comment on negotiations, and other observations at Patriots training camp

The 29-year old Ward had two years remaining on a five-year, $100 million contract he signed in 2022.

Read more Fractured wrist sidelines Curtis Mead and leaves Red Sox without the newly acquired slugger indefinitely

Ward — who grew up less than an hour from Cleveland in Macedonia — is Cleveland’s longest-tenured player after the franchise traded reigning AP Defensive Player of the Year Myles Garrett to the Rams in June. Ward was the fourth overall pick in the 2018 draft out of Ohio State.

Since entering the league in 2018, he leads the NFL with 104 passes defensed, and his 18 interceptions are tied for 19th. Ward had 39 tackles and picked off one pass in 15 games last season.

Read more Follow live updates on the Trump administration

Post Comment